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Given: m/AOB = 42°
m/EOF= 66°
Prove: m/COD = 72°
B
m

Complete the proof.
It is given that mZAOB = 42° and m/EOF= 66°. By the
m/BOC 66°. By the
m/AOC + m/COD
V
180°. After application of the
m/AOC =
108°, and by the
✓ZEOF ZBOC. Therefore,
m/COD = 72°.

1 Answer

5 votes

Final answer:

The answer explains how to use properties of vertical angles, linear pairs, and angles around a point to find unknown angles in geometric figures. Without a diagram, the answer provides a general method for solving such problems using algebra based on these properties.

Step-by-step explanation:

The problem seems to be about determining an unknown angle within a geometric figure, given certain angles are known. Without a diagram or more context it's challenging to provide a precise proof. However, I will demonstrate a general approach on how to solve for an unknown angle.

When you have intersecting lines, you can usually find unknown angles using properties of vertical angles, linear pairs, or angles around a point. Vertical angles are equal, the angles in a linear pair sum up to 180 degrees, and the angles around a point sum up to 360 degrees. By applying these rules, you can solve for the unknown angles using the provided angle measurements.

Let's assume in our case that point O is the center of these intersecting lines. This would mean that if m/AOB = 42° and m/EOF= 66°, and these lines intersect in such a way that they form vertical angles or linear pairs, we could use algebra to calculate m/COD based on the information given and the properties mentioned above.

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