Answer:
The extension of the spring for a 3N weight would be approximately 24.49 meters.
Step-by-step explanation:
To find the extension of the spring for a 3N weight, we can use Hooke's Law, which states that the force required to extend or compress a spring is directly proportional to the displacement (extension or compression) of the spring. The formula for Hooke's Law is:
F = k * x
where:
F = Force applied to the spring (in Newtons)
k = Spring constant (a measure of the stiffness of the spring) in N/m (Newtons per meter)
x = Extension or compression of the spring (in meters)
First, we need to find the spring constant (k) using the given information for the 50g mass and its extension:
Given:
Force (F) = 0.050 kg * 9.8 m/s^2 (acceleration due to gravity)
Extension (x) = 4 mm = 0.004 m
Now, let's calculate the spring constant:
F = k * x
k = F / x
k = (0.050 kg * 9.8 m/s^2) / 0.004 m
k = 0.1225 N/m
Now that we have the spring constant, we can find the extension (x) for the 3N weight:
Given:
Force (F) = 3 N
Spring constant (k) = 0.1225 N/m
Using the same formula:
F = k * x
x = F / k
x = 3 N / 0.1225 N/m
x = 24.49 m
The extension of the spring for a 3N weight would be approximately 24.49 meters.
( I dont know if im right though)