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PLEASE HELP ILL GIVE 80 POINTS SOMEONE DO THIS FOR ME ITS GEOMETRY

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User Dtyler
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2. m = 1/2. Lines that are parallel to each other have the same slope.

3. m = 4

First, find the slope of the original line using (y₂-y₁)/(x₂-x₁)

(-13 + 5)/(15 + 17) = -1/4

Lines that are perpendicular to each other have slopes that are the negative reciprocals of each other. So basically, flip the -1/4 into -4/1 and make it positive which results in m = 4.

4. m = -4/5. As I mentioned before, lines that are parallel to each other have the same slope.

5. m = -1. Find the negative reciprocal of 1 since the lines are perpendicular.

6. m = 1/3. Find the negative reciprocal of -3 since the lines are perpendicular.

7. m = -1

Find the slope by using (y₂-y₁)/(x₂-x₁)

(-16 + 10)/(8 - 2) = -1. Since the lines are parallel, the slopes are the same.

8. m = 10/3

Get the equation in the form y = mx+b

3y = 10x - 3

Divide the entire equation by 3

y = (10/3)x - 1.

10/3 is in the place of m, so m = 10/3. Since the lines are parallel, the slopes are the same.

9. m = -5/6

Get the equation in the form of y = mx+b

6x - 5y = 11

Subtract 6x on both sides

-5y = 11 - 6x

Divide the entire equation by -5

y = (-11/5) + (6/5)x

Now rearrange the equation

y = (6/5)x - 11/5

6/5 is in the place of m, so m = 6/5. Since the lines are perpendicular to each other, find the negative reciprocal of 6/5 which is -5/6.

10. m = 1/7

The equation is already in the form of y = mx+b, and we can see that -7 is in place of m. Since the lines are perpendicular to each other, find the negative reciprocal of -7 which is 1/7.

User Tuxxi
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