Answer:
17.06
Explanation:
for every right triangle with vertices on the same circle perimeter, the hypotenusa must be the diameter
dia. = 12 cm
radius = 12 ÷ 2 = 6 cm
CD² = CE² + DE²
12² = 9.09² + DE²
DE² = 144 - 82.6281
DE² = 61.3719
DE² = EF² + FD² - 2(EF)(FD)cos∠EFD
61.3719 = 6² + 6² - 2(6)(6)cos∠EFD
cos∠EFD = 0.1476
∠EFD = 81.5114°
arc ED = 81.5114°/360° × circle perimeter
= 81.5114°/360° × 3.14 × 12
= 17.06