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If 6000 joule of heat is added to 20 GM of water at 25°c.what will be it's temperature

User Arcane
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Answer:

In this case, the heat energy added (Q) is 6000 J, the mass (m) of the water is 20 GM (which is equivalent to 20,000,000 grams), and the initial temperature (T) is 25°C. So, the final temperature of the water would be approximately 25.0000718°C.

User BBaysinger
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