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Sin77*sin88+cos77*cos88

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Note: Numbers next to functions are in degrees.

1 Answer

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Answer:


\sf cos(77) * cos(88) + sin(77) * sin(88) =\boxed{\sf cos(11) \approx 0.982}

Explanation:

To simplify the expression
\sf sin(77) * sin(88) + cos(77) * cos(88), we'll use trigonometric identities.

The identity we'll use is the product-to-sum formula for cosine:


\boxed{\sf cos(A - B) = cos(A) * cos(B) + sin(A) * sin(B)}

Now, let A = 77 and B = 88


\sf cos(77 - 88) = cos(77) * cos(88) + sin(77) * sin(88)

Notice that 77 - 88 = -11 degrees.


\sf cos(-11) = cos(77) * cos(88) + sin(77) * sin(88)

Now, we know that cos(-x) = cos(x), so:


\sf cos(11) = cos(77) * cos(88) + sin(77) * sin(88)

Finally, since the cosine function is even (cos(x) = cos(-x)), we have:


\sf cos(11) = cos(77) * cos(88) + sin(77) * sin(88) = cos(-11)

Therefore:


\sf cos(77) * cos(88) + sin(77) * sin(88) =\boxed{\sf cos(11) \approx 0.982}

See the attachment for trigonometric identities formula:

Sin77*sin88+cos77*cos88 **HELP ASAP** Note: Numbers next to functions are in degrees-example-1
User Sergio Gonzalez
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