Question

Eva spent $48 on a shirt and a pair of pants. The pants cost twice as much as the shirt. How much did each item cost? Let s stand for the cost of the shirt. Equation: 16-73/2 The shirt cost S= 48 The pants cost 2 how much dose the shirt cost and the pants​

Answer 1

Eva spent a total of $48 on the shirt and the pair of pants. So, we can write the equation:

s + 2s = 48

Simplifying the equation, we get:

3s = 48

Now, we can solve for 's' by dividing both sides of the equation by 3:

s = 48 / 3

s = 16

Therefore, the shirt costs $16. To find the cost of the pants, we simply double the cost of the shirt:

2s = 2 * 16 = 32

Hence, the pants cost $32.



Solution:

- The shirt costs $16.
- The pants cost $32.

Answer 2

Let's use algebra to solve the problem:

Let s be the cost of the shirt. Since the pants cost twice as much as the shirt, the cost of the pants would be 2s.

According to the given information, Eva spent $48 on the shirt and pants combined:

s + 2s = 48

Combining like terms:

3s = 48

To solve for s, we divide both sides of the equation by 3:

s = 48 / 3
s = 16

Therefore, the shirt costs $16.

To find the cost of the pants, we substitute the value of s into the expression for the pants' cost:

2s = 2 * 16
2s = 32

Therefore, the pants cost $32.

In summary:
The shirt costs $16 and the pants cost $32.