Y is inversely proportional to the square of x. If Y = 9 when x = 3, then what is y, when x is 6?

Question

asked Sep 10, 2024 222k views

1 Answer

Hamid Yusifli · Answer 1 · 2024-09-14T01:07:33+0000

Answer:

y =
(9)/(4)

Explanation:

given Y is inversely proportional to x² then the equation relating them is

Y =
(k)/(x^2) ← k is the constant of proportionality

to find k use the condition if Y = 9 when x = 3 , then

9 =
(k)/(3^2) =
(k)/(9) ( multiply both sides by 9 )

81 = k

Y =
(81)/(x^2) ← equation of proportion

when x = 6 , then

Y =
(81)/(6^2) =
(81)/(36) =
(9)/(4)