Question

Diagonals AC and BD of a rhombus ABCD meet at O . If AC=8cm and BD=6cm , find sin √OCD.

Answer 1

Hi,

Explanation:

AC=8 => AO=OC=AC/2=4

BD=6 => BO=OD=3

`sin(\widehat{OCD})\\\\=(OD)/(√(OD^2+OC^2))\\\\=(3)/(√(3^2+4^2) )\\\\\\=\boxed{(3)/(5)}`