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The load to a 3-phase supply consists of three similar coils connected in star. The line current are 25A and the KVA and KW inputs are 20 and 11 respectively. Fine (I) phase and line voltage (Ii) the KVAR inputs (iii) resistance and reactance of each coils



User Chrisss
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1 Answer

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Step-by-step explanation:

KVA power input = 20.

Power kW input = 11.

power factor = Cos φ = 11/20 = 0.55, Φ = 56.63°.

Line current = I = 25A = phase current.

Real power = 11 kW = 3 I² R = 3 Iph × Vph × Cos φ

=> R = 11000/(3×25² ) = 5.87 Ohm.

Phase voltage RMS = Vph = kW /(3 I Cosφ)

= 11000/ (3 × 25 × 0.55) = 266.67 V.

Line voltage Vʟ= √3 × Vph = 461.87 V.

(ii) KVAR input = √(20² - 11²) = 3 √31 = reactive power.

f = 60Hz. ω = 2π f = 120π rad/s.

3 I² Zi = 3√31 × 1000

Zi = √31 ×1000 ÷ 25² = 8.91 Ohm.

Zi = ω L

=> L = 23.64 μH.

(iii) Resistance = R = 5.87 Ohm.

Reactance = √(R²+ ω² L²) = 10.67 Ohm.

User Vincent Malgrat
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