Question

Use the following information for questions 18 - 21. A 0.13 kg disk is rotating at an angular speed of 57 rad/s. The disk has a radius of 0.25 m. The disk speeds up for 3 s. After the 3 s have passed, the edge of the disk is under a centripetal force of 312.13 N. What is the centripetal acceleration of the disk at this time

Answer 1

`a=2401m/s^2`

Step-by-step explanation:

From the question we are told that:

Mass
`m=0.13kg`

Angular speed
`\omega=57rads/s`

Radius
`r=0.25m`

Time
`t=3s`

`F=312.13N`

Generally the equation for centripetal acceleration is mathematically given by

`a=(f)/(m)`

`a=(312.13)/(0.13)`

`a=2401m/s^2`