Answer:
probability that a random point on AK will be on BH = 3/5
Explanation:
length of line segment BH = 12
as the distance from point B to point H on the line segment = 12
and the distance from starting point A to end point K equals = 20
probability that a random point on line AK will be on BH =
12/20 = 6/10 = 3/5