To calculate the molecular mass of Pb(NO3)2 (lead(II) nitrate), you need to add the atomic masses of all the elements in the chemical formula.
The atomic masses of the elements are as follows:
Pb (lead) = 207.2 g/mol
N (nitrogen) = 14.01 g/mol
O (oxygen) = 16.00 g/mol
Now, let's calculate the molecular mass:
Molecular mass of Pb(NO3)2 = (Pb mass) + (2 * N mass) + (6 * O mass)
Molecular mass of Pb(NO3)2 = (207.2 g/mol) + (2 * 14.01 g/mol) + (6 * 16.00 g/mol)
Molecular mass of Pb(NO3)2 = 207.2 g/mol + 28.02 g/mol + 96.00 g/mol
Molecular mass of Pb(NO3)2 = 331.24 g/mol
The molecular mass of Pb(NO3)2 (lead(II) nitrate) is approximately 331.24 g/mol.