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Solve the linear-quadratic system of equations algebraically. Express your values as radical expressions, if necessary.

y=5x
y=
3^(x)

User Eric Wu
by
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1 Answer

4 votes

Answer:

The approximate solution to the system of equations is x ≈ 0.9103 and y ≈ 4.5515.

Explanation:

To solve the linear-quadratic system of equations algebraically, we need to set the two expressions for y equal to each other:

y = 5x

y = 3^x

Setting these equations equal to each other:

5x = 3^x

Now, to solve for x, we need to isolate the variable x. One way to do this is to take the logarithm of both sides. Let's use the natural logarithm (ln):

ln(5x) = ln(3^x)

Now, we can use the properties of logarithms to simplify the equation:

ln(5x) = x * ln(3)

Next, isolate x:

x = ln(5x) / ln(3)

Since the x appears on both sides of the equation, it's not straightforward to find the exact value of x algebraically. We can use numerical methods or calculators to find an approximate value for x:

x ≈ 0.9103

So, the approximate solution to the system of equations is x ≈ 0.9103. To find the corresponding value of y, we can use either of the original equations. Let's use the first equation:

y = 5x

y ≈ 5 * 0.9103

y ≈ 4.5515

User Gert Vaartjes
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