Question

Pls help with this question, thanks!

Answer 1

Slope of PQ:

`m = (8 - 2)/(3 - 1) = (6)/(2) = 3`

2 = 3(1) + b

2 = 3 + b

b = -1

y = 3x - 1

To obtain the equation of the line parallel to PQ through R:

5 = 3(12) + b

5 = 36 + b

b = -31

y = 5x - 31

Midpoint of QR:

((3 + 12)/2, (8 + 5)/2) = (15/2, 13/2) =

(7.5, 6.5)

Slope of QR:

`m = (8 - 5)/(3 - 12) = (3)/( - 9) = - (1)/(3)`

To obtain the equation of the line perpendicular to QR through the midpoint of QR:

13/2 = 3(15/2) + b

13/2 = 45/2 + b

b = -32/2 = -16

y = 3x - 16