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How many grams of Al are needed to react with 79.8 g of FeO given the following reaction: 3FeO + 2Al --> 3Fe + Al2O3

1 Answer

4 votes
From equation,
3 mol FeO reacts with 2 mol Al

Finding mass of FeO
no of mol=mass/Mr
3=mass/(55.8+16)
mass = 215.4g

Finding mass of Al
no of mol= mass/Ar
2= mass/27
mass=54g

215.4g of FeO reacts with 54g Al
79.8g of FeO reacts with 54/215.4 × 79.8 = 20g Al
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