Question

Can someone answer this?

Answer 1

A) Acidic

B) Basic

Step-by-step explanation:

a. To find the pH of a solution with a hydrogen ion concentration of [H^+] = 2.3 × 10^-3, we can use the following equation:

⇒ pH = -log[H+]

Substituting the given value of [H^+], we get:

⇒ pH = -log(2.3 × 10^-3) ≈ 2.64

Since this pH value is less than 7, the solution is acidic.

b. To find the pH of a solution with a hydroxide ion concentration of [OH^-] = 2.3 × 10^-3, we can first find the hydrogen ion concentration using the following equation:

⇒ Kw = [H+][OH^-] = 1.0 × 10^-14

⇒ [H+] = Kw/[OH^-] = (1.0 × 10^-14)/(2.3 × 10^-3) ≈ 4.35 × 10^-12

Then, we can find the pH using the equation from part (a):

⇒ pH = -log[H+] = -log(4.35 × 10^-12) ≈ 11.36

Since this pH value is greater than 7, the solution is basic.

Answer 2

Note: Substances having pH level less than 7 are acids; substances having pH more than 7 are bases and the substances having pH equal to 7 are neutral.

pH + pOH = 14

pH = -log[H+]

pOH = -log[OH-]

Answer:

`3a.\ \mathrm{Solution:}\\\mathrm{[H^+]=2.3* 10^(-3)}\\\mathrm{or,\ -log[H^+]=-log(2.3* 10^(-3))}\\\mathrm{or,\ pH=2.638}`

`\mathrm{So,\ this\ is\ an\ acid.}`

`3b. \mathrm{Solution:}\\\mathrm{[OH^-]=2.3* 10^(-3)}\\\mathrm{or,\ -log[OH^(-)]=2.3* 10^(-3)}\\\mathrm{or,\ pOH=2.638}\\\mathrm{Now,}\\\mathrm{pH+pOH=14}\\\mathrm{or,\ pH=14-2.638}\\\mathrm{or,\ pH=11.36}\\\mathrm{So,\ this\ is\ a\ base.}`