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when the volume iron (lll) nitrate (mL) is 10.00 and the volume potassium thiocyanate (mL) is 2.00 and the volume Dl water is 8.00 (mL) what is the concentration iron (lll) thiocyanate ion in stock solution (M)

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Step-by-step explanation:

To calculate the concentration of iron (III) thiocyanate ion in the stock solution, we need to know the molar amounts of iron (III) nitrate and potassium thiocyanate used.

Assuming that the iron (III) nitrate and potassium thiocyanate are both fully dissociated in water and react in a 1:1 stoichiometric ratio, we can use the volume and concentration information to calculate the concentration of the iron (III) thiocyanate ion.

Let's assume the molar concentration of the iron (III) nitrate solution is C1 (in M) and the molar concentration of the potassium thiocyanate solution is C2 (in M).

The volume (V) of the iron (III) nitrate solution is 10.00 mL, and the volume (V) of the potassium thiocyanate solution is 2.00 mL. The volume of water added is 8.00 mL.

Since the volume of the final solution is the sum of the volumes of the iron (III) nitrate, potassium thiocyanate, and water, we have:

V_final = V_iron_nitrate + V_potassium_thiocyanate + V_water

V_final = 10.00 mL + 2.00 mL + 8.00 mL

V_final = 20.00 mL

Now, we can calculate the concentration of the iron (III) thiocyanate ion (C_iron_thiocyanate) in the stock solution using the formula:

C_iron_thiocyanate = (n_iron_thiocyanate) / V_final

Since the reaction is stoichiometric and balanced, the number of moles of iron (III) thiocyanate formed will be equal to the number of moles of iron (III) nitrate and potassium thiocyanate reacted.

n_iron_thiocyanate = n_iron_nitrate = n_potassium_thiocyanate

The molar amounts of iron (III) nitrate and potassium thiocyanate can be calculated using their respective concentrations and volumes:

n_iron_nitrate = C1 * V_iron_nitrate

n_potassium_thiocyanate = C2 * V_potassium_thiocyanate

Since the stoichiometric ratio between iron (III) nitrate and potassium thiocyanate is 1:1, we can set n_iron_nitrate = n_potassium_thiocyanate.

C_iron_thiocyanate = (n_iron_thiocyanate) / V_final

C_iron_thiocyanate = (n_iron_nitrate) / V_final

C_iron_thiocyanate = (C1 * V_iron_nitrate) / V_final

Substituting the given values:

C_iron_thiocyanate = (C1 * 10.00 mL) / 20.00 mL

To calculate the concentration of the iron (III) thiocyanate ion in the stock solution, we need to know the molar concentration (C1) of the iron (III) nitrate solution. Without that information, we cannot provide a specific numerical value for the concentration.

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