Question

Given the function, calculate the following values:

Answer 1

Answer: f(2)=22, f(-2)=6, f(x+1) = 4x^2+12x+6, f(-x) = 4x^2-4x-2

Explanation:

For x = 2:

f(2) = 4(2)^2 + 4(2) - 2

f(2) = 22

For x = -2:

f(-2) = 4(-2)^2 + 4(-2) - 2

f(-2) = 6

For x = x + 1:

f(x + 1) = 4(x + 1)^2 + 4(x + 1) - 2

f(x + 1) = 4(x^2 + 2x + 1) + 4x + 4 - 2

f(x + 1) = 4x^2 + 12x + 6

For x = -x:

f(-x) = 4(-x)^2 + 4(-x) - 2

f(-x) = 4x^2 - 4x - 2