Answer:
option B .
Step-by-step explanation:
Here all resistors are connected in series to a potential of 120V .
So here the net resistance would be the sum of all resistors,
= 10 + 20 + 30 = 60Ω
By Ohm's law ,
Voltage = current*resistance
on substituting the respective values, we have ;
120 = I * 60
I = 120/60
I = 2 A
In series current flow is same through all resistors so , the current 10Ω resistance is 2 amperes.