Question

Write the equation of the circle with center (-11,-14) and radius 3.

Answer 1

equation of circle: (x+11)^2 + (y+14)^2 = 9

Explanation:

the standard form of a circle equation is:
(x-h)^2 + (y-k)^2 = r^2

since we have our centre values (h,k) and our radius, we just have to plug them into the equation form

(x--11)^2 + (y--14)^2 = 3^2

thus, (x+11)^2 + (y+14)^2 = 9

Answer 2

Given :

• Radius = 3
• h = -11
• k = -14

To find :

• The equation of the circle

Solution :

We know that,

The equation of a circle is :

`\rightarrow(x - h) {}^(2) + (y - k) {}^(2) = {r}^(2)`

Inserting the values we have been given,

`\rightarrow(x - ( - 11)) {}^(2) + (y - ( - 14)) {}^(2) = {3}^(2) \\`

`\rightarrow(x + 11) {}^(2) + (y + 14) {}^(2) = 9`

Therefore,the equation of the circle would be (x+11)² +(y+14)² = 9.