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A model rocket is launched from the top of a building. The height (in meters) of the rocket above the ground is given by h(t) = -6t2 +24t +14, where t is the time (in seconds) since the rocket was launched. What is the rocket’s maximum height?

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Answer:

rocket's maximum height = 38 meters

Explanation:

maximum height is reached when t = -b/2a

equation: h(t) = -6t^2 + 24t + 14

-24/2(-6)

-24/-12 = 2

time = 2 seconds

plug 2 into the equation

-6(2^2) + 24(2) + 14

-6(4) + 48 + 14 = ?

-24 + 48 + 14 = ?

= 38

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