Explanation:
To prove that ΔABC and ΔEDC are similar triangles, we need to show that their corresponding angles are congruent and their corresponding sides are proportional.
Given information:
Angles A and E are right angles (90 degrees).
AC = 4, AB = 3, BC = 5, DC = 15, DE = 9, and CE = 12.
Step 1: Show that corresponding sides are proportional:
We have:
AC / DE = 4 / 9
AB / DC = 3 / 15
BC / CE = 5 / 12
We notice that AC / DE, AB / DC, and BC / CE are all equal to 4 / 9. Therefore, the corresponding sides are proportional.
Step 2: Show that corresponding angles are congruent:
Angles A and E are both right angles (90 degrees). All right angles are congruent.
Step 3: Apply the SSS Similarity Postulate:
Since the corresponding sides are proportional, and the corresponding angles are congruent, we can apply the SSS (Side-Side-Side) Similarity Postulate to conclude that ΔABC ~ ΔEDC.
So, the correct statement is: 15 over 4 equals 12 over 9 equals 9 over 3 shows the corresponding sides are proportional; therefore, ΔABC ~ ΔEDC by the SSS Similarity Postulate. ∠E and ∠A are right angles; therefore, these angles are congruent since all right angles are congruent.