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If z is a standard normal variable, (a) Find p(z<1.34) (b) Find the area to the right of 2.26 (c) Find the probability that z lies between -1.21 and 2.11 (d) Find P (subscript) 73 (e) find z (subscript) 0.429
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If z is a standard normal variable, (a) Find p(z<1.34) (b) Find the area to the right of 2.26 (c) Find the probability that z lies between -1.21 and 2.11 (d) Find P (subscript) 73 (e) find z (subscript) 0.429

User Phuongle
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(a) P(z < 1.34) ≈ 0.9099.
(b) The area to the right of 2.26 ≈ 0.9883.
(c) The probability that z lies between -1.21 and 2.11 ≈ 0.8735.
(d) The 73rd percentile ≈ 0.63.
(e) z₀.₄₂₉ ≈ 1.67. <- answer.
User Snorbuckle
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7.9k points
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