Question

The density of gold (Au) is 19.3 g/cm3 and that of iron (Fe) is 7.9 g/cm3. A comparison of the volumes (V) of 50 gram samples of each metal would show that:

Answer 1

Step-by-step explanation:

AI-generated answer

To compare the volumes of 50 gram samples of gold (Au) and iron (Fe), we can use the formula:

Density = Mass / Volume

We are given the densities of gold (19.3 g/cm3) and iron (7.9 g/cm3). Let's calculate the volumes of the samples:

1. Gold (Au):

Density of gold = 19.3 g/cm3

Mass of the gold sample = 50 grams

Using the formula, we can rearrange it to solve for volume:

Volume = Mass / Density

Volume of the gold sample = 50 g / 19.3 g/cm3 = 2.59 cm3

2. Iron (Fe):

Density of iron = 7.9 g/cm3

Mass of the iron sample = 50 grams

Using the formula, we can rearrange it to solve for volume:

Volume = Mass / Density

Volume of the iron sample = 50 g / 7.9 g/cm3 = 6.33 cm3

Comparing the volumes of the 50 gram samples, we find that the volume of the gold sample is 2.59 cm3 and the volume of the iron sample is 6.33 cm3. Therefore, the comparison of the volumes shows that the iron sample has a larger volume than the gold sample.

Answer 2

Comparing the volumes (V) of 50 gram samples of gold (Au) and iron (Fe) would show that the volume of the gold sample is smaller than the volume of the iron sample. Since gold has a higher density of 19.3 g/cm³ compared to the density of iron, which is 7.9 g/cm³, the same mass of gold occupies a smaller volume compared to iron. This indicates that gold is denser than iron.