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Given that sin θ = 6/9, calculate tan θ

User Jondykeman
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To calculate tan θ, we can use the relationship between sine (sin θ) and tangent (tan θ):

tan θ = sin θ / cos θ

To find the value of tan θ, we need to determine the value of cos θ. We know that sin θ = 6/9, and we can use the Pythagorean identity to find cos θ:

cos^2 θ + sin^2 θ = 1

Since sin θ = 6/9, we can substitute it in the equation:

cos^2 θ + (6/9)^2 = 1

Simplifying:

cos^2 θ + 36/81 = 1

cos^2 θ = 1 - 36/81

cos^2 θ = 45/81

Now, find the value of cos θ:

cos θ = √(45/81) ≈ √(5/9) ≈ √(5) / 3

Now, we can calculate tan θ:

tan θ = sin θ / cos θ

tan θ = (6/9) / (√(5) / 3)

tan θ = (6/9) * (3 / √(5))

tan θ = 18 / (9 * √(5))

tan θ = 2 / √(5)

To rationalize the denominator, multiply both the numerator and denominator by √(5):

tan θ = (2 / √(5)) * (√(5) / √(5))

tan θ = 2√(5) / 5

So, the value of tan θ is 2√(5) / 5.

User Dugini Vijay
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