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The line has a slope of 3 and passes through the point (-3,0). What is the point-slope form of the line? A) y-3=3(x+3) B) y-0=3(x+3) C) y-3= (x+3) D) y-0=3(x-3)​

User Dlavila
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2 Answers

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Given that

  • A line has a slope of 3 and it passes through (-3,0)

✦ We need to find

  • The point-slope form of the line


\hrulefill


\longleftrightarrow\rm{y-y_1=m(x-x_1)}


\longleftrightarrow\rm{y-0=3(x-(-3)}


\longleftrightarrow\rm{y=3(x+3)}

Therefore the point slope is y = 3(x + 3).

User Crawf
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Required answer: y - 0 = 3(x + 3)

Detailed solution:

Let's take a look at our givens.

This line:

  • Has a slope of 3
  • Passes through (-3,0)

We can substitute this info into point-slope:


\dashrightarrow\bf{y-0=3(x-(-3)}


\dashrightarrow\bf{y-0=3(x+3)} (point-slope)


\dashrightarrow\bf{y=3(x+3)


\dashrightarrow\bf{y=3x+9}


\therefore The line's equation is y - 0 = 3(x + 3).


\hrulefill

Have a wonderful day! <3

User Alexqinbj
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