Question

What is the solution to –2(8x – 4) < 2x + 5?

x > x is greater than StartFraction 1 Over 6 EndFraction.
x < x is less than StartFraction 1 Over 6 EndFraction.
x > 6
x < 6

Answer 1

✦ Given that

• -2(8x - 4) < 2x + 5

✦ We need to find

• the value of x

`\longleftrightarrow\rm{-2(8x-4) < 2x+5}`

`\longleftrightarrow\rm{-16x+8 < 2x+5}`

`\longleftrightarrow\rm{-16x-2x+8 < 5}`

`\longleftrightarrow\rm{-18x < 5-8}`

`\longleftrightarrow\rm{-18x < -3}`

`\longleftrightarrow\rm{18x > 3}`

`\longleftrightarrow\rm{x > (3)/(18)}`

`\longleftrightarrow\rm{x > (1)/(6)}`

Therefore x > 1/6

Answer 2

The solution to –2(8x – 4) < 2x + 5 is:

-128x + 64 < 2x + 5
-130x < -59
x > 59/(-130)
x > -0.454

Therefore, the answer is x > x is greater than StartFraction 1 Over 6 EndFraction.