Answer:
To find the equation of a line parallel to y = -7x - 2 and passing through the point (-9,-12), we can use the fact that parallel lines have the same slope.
The given line is in slope-intercept form, which is y = mx + b, where m is the slope. In this case, the slope is -7.
To find the equation of the parallel line, we can use the point-slope form of a linear equation, which is:
y - y1 = m(x - x1)
Substituting the values into the equation, we have:
y - (-12) = -7(x - (-9))
Simplifying, we get:
y + 12 = -7(x + 9)
Expanding, we have:
y + 12 = -7x - 63
Next, we can isolate y by subtracting 12 from both sides:
y = -7x - 75
Therefore, the equation of the line parallel to y = -7x - 2 and passing through the point (-9,-12) in slope-intercept form is y = -7x - 75.
Explanation: