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Helpppppppppppppppppppppppppp

Helpppppppppppppppppppppppppp-example-1
User Gkephorus
by
9.0k points

1 Answer

3 votes

1)

In ∆ABC,

Using the law of sines,


\rightarrow (a)/( \sin(A) ) = (b)/( \sin(B) )

where,

  • a = 8cm
  • b = ?
  • Sin A = Sin 35
  • Sin B = Sin 80


\rightarrow (8cm)/( \sin(35) ) = (b)/( \sin(80) )


\rightarrow (8cm)/( 0.57 ) = (b)/( 0.98 )


\rightarrow 0.57b = 8cm * 0.98


\rightarrow 0.57b =7.84cm


\rightarrow b = (7.84cm)/(0.57) \\


\rightarrow b =13.8cm

hence , Side AC = 13.8cm.

In ∆ ACD ,

Using the law of sines,


\rightarrow (a)/( \sin(A) ) = (b)/( \sin(B) )

where,

  • a = x
  • b = 13.8cm
  • Sin(A) = Sin 75
  • Sin(B) = Sin 60


\rightarrow (x)/( \sin(75) ) = (13.8cm)/( \sin(60) ) \\


\rightarrow (x)/( 0.97) = (13.8cm)/( 0.87 ) \\


\rightarrow 0.87x = 13.8cm * 0.97


\rightarrow 0.87x = 13.39cm


\rightarrow x = (13.39cm)/(0.87) \\


\rightarrow x = 15.4cm

Hence, the value of x would be equal to 15.4cm .

Helpppppppppppppppppppppppppp-example-1
Helpppppppppppppppppppppppppp-example-2
User Jasper Lankhorst
by
8.3k points

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