Question

A sample of gas is at atmospheric pressure 1atm and has a volume 0.05dm3. d. Determine the new volume if the pressure is reduced to 0.8 atm.​

Answer 1

To determine the new volume, you can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume, assuming the temperature remains constant.

Boyle's Law equation: P₁V₁ = P₂V₂

P₁ = initial pressure = 1 atm

V₁ = initial volume = 0.05 dm³

P₂ = final pressure = 0.8 atm

V₂ = final volume (to be determined)

Substituting the given values into Boyle's Law equation:

1 atm * 0.05 dm³ = 0.8 atm * V₂

0.05 dm³ = 0.8 atm * V₂

Dividing both sides of the equation by 0.8 atm:

0.05 dm³ / 0.8 atm = V₂

V₂ ≈ 0.0625 dm³

Therefore, the new volume of the gas, when the pressure is reduced to 0.8 atm, is approximately 0.0625 dm³.

Answer 2

Okay, let's solve this step-by-step:

* We are given:

- Initial pressure = 1 atm

- Initial volume = 0.05 dm^3

- Final pressure = 0.8 atm

* For gases, we can use Boyle's Law:

P1V1 = P2V2

Where:

P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume (what we want to find)

* Substituting the known values:

(1 atm)(0.05 dm^3) = (0.8 atm)V2

V2 = (1 atm)(0.05 dm^3) / (0.8 atm)

* Solving:

V2 = (0.05 dm^3) / (0.8)

V2 = 0.0625 dm^3

Therefore, when the pressure is reduced from 1 atm to 0.8 atm, the volume of the gas will increase from 0.05 dm^3 to 0.0625 dm^3.