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2x2+kx+3=0 find the values of k for each of the following quadratic equations s that they have two equal roots

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Okay, let's solve this step-by-step:

We have the quadratic equation: 2x^2 + kx + 3 = 0

For the quadratic equation to have equal roots, the discriminant (b^2 - 4ac) must be equal to 0.

The discriminant for this equation is: (k^2 - 8*2*3) = k^2 - 48

Setting this equal to 0 and solving for k gives us:

k^2 - 48 = 0

k^2 = 48

k = +/- 6

Therefore, the values of k that give the equation two equal roots are:

k = +6 and k = -6

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