Question

A bomb Explods into 2 pieces. The mass of 1 piece is double of the mass of other. After Explosion if the lighter fragment moves with 100m/s "Find the speed of other fragment.

please send answer with full explanation using 9th grade formulas ​

Answer 1

Okay, here are the steps to solve this problem:

1. Let's define variables:

Total mass before explosion = m

Mass of lighter fragment = x

Mass of heavier fragment = 2x

2. Since the mass of the heavier fragment is double the mass of the lighter fragment, we can write:

2x = double x, so x = half of 2x

3. The total mass before the explosion was the sum of the 2 masses after explosion:

m = x + 2x

m = 3x

4. The lighter fragment moves with a velocity of 100 m/s after explosion, so:

Velocity of lighter fragment = 100 m/s

5. From the conservation of momentum, we know that the total momentum before explosion is equal to the total momentum after explosion. The total momentum before explosion is 0, since the bomb was at rest. The total momentum after explosion is:

Momentum of lighter fragment + Momentum of heavier fragment = 0

(x)(100) + (2x)v = 0 where v is the unknown velocity of the heavier fragment

6. Solving for v:

(x)(100) + (2x)v = 0

2xv + 100x = 0

2xv = -100x

v = -50 m/s

So the velocity of the heavier fragment is -50 m/s.

The explanation uses the conservation of momentum and the fact that the mass of the heavier fragment is double the mass of the lighter fragment. Let me know if you have any other questions!