1) dy/dt = y has the general solution y = Ce^t where C is any constant.
2) We need to find f(t) such that f'(t)= t/f(t)^2 and f(1) = 2. The solution is f(t) = sqrt(t^2 + 4).
3) The general solution to dy/dt = t^3y is y = Ce^{t^4/4}
4) The general solution to the logistic equation is y = 1/(1+Ce^(-2t)) which describes
S-shaped curves where y approaches 1 as t approaches infinity.
5) (a) V_cap = V_bat(1-e^(-t/RC)) where R is the resistance and C is the capacitance.
(b) Plugging in V_cap = 1.45 and V_bat = 2.7 into the equation, and solving for t yields
t = -270ln(0.535) = 416 seconds