Question

Determine the molarity of a solution made by dissolving 1.31 moles of CaCl2 in enough water to make 250.0 mL of solution.

Answer 1

5.24moles/L

Step-by-step explanation:

To determine the molarity (M) of a solution, we use the formula:

Molarity (M) = Number of moles of solute / Volume of solution in liters

Given:

Number of moles of CaCl2 = 1.31 moles

Volume of solution = 250.0 mL = 250.0 mL / 1000 mL/L (since 1 L = 1000 mL) = 0.250 L

Now, let's calculate the molarity:

Molarity (M) = 1.31 moles / 0.250 L

Molarity (M) = 5.24 moles/L

Therefore, the molarity of the CaCl2 solution is 5.24 moles/L.