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How to convert from standard to vertex from: 0=5x^2-15x+1

User Tmt
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Answer: To convert a quadratic equation from standard form (also known as general form) to vertex form, you need to complete the square. The vertex form of a quadratic equation is given by:

y = a(x - h)^2 + k,

where (h, k) represents the coordinates of the vertex, and 'a' is a constant representing the stretch or compression of the parabola.

Let's convert the given equation from standard form (0 = 5x^2 - 15x + 1) to vertex form (y = a(x - h)^2 + k):

Step 1: Factor out the common coefficient (if not already done).

0 = 5(x^2 - 3x) + 1.

Step 2: Complete the square inside the parentheses:

To complete the square for x^2 - 3x, we need to add and subtract the square of half of the coefficient of x, which is (3/2)^2 = 9/4.

0 = 5(x^2 - 3x + 9/4 - 9/4) + 1.

Step 3: Group the square term with the constant term:

0 = 5[(x - 3/2)^2 - 9/4] + 1.

Step 4: Distribute the common coefficient back:

0 = 5(x - 3/2)^2 - 45/4 + 1.

Step 5: Simplify the constant terms:

0 = 5(x - 3/2)^2 - 41/4.

Now, we have the equation in vertex form: y = 5(x - 3/2)^2 - 41/4.

The vertex of the parabola is (3/2, -41/4). The 'a' value is 5, representing that the parabola is stretched vertically.

User Janning Vygen
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