Answer:
So If we assume the linear rate of water loss over time, it would take 20 years to lose 1.75 trillion gallons (from 5.7 trillion to 3.95 trillion).
Therefore, if the rate of water loss continues at the same pace, it will take approximately 20 years from today for Lake Mead to reach 10% of its capacity.
Explanation:
Currently, the lake is at 38% of its capacity, meaning it has already lost 62% of its water. If the rate of loss continues at 62% over the next 20 years, we can calculate how much water will remain in the lake after those 20 years.
Using proportions, we know that if 62% represents 9.3 trillion gallons, then 100% (the lake’s full capacity) represents 9.3 trillion gallons / 0.62 = 15 trillion gallons.
If the lake loses 62% of its water over 20 years, it will retain 38% of 15 trillion gallons, which is 15 trillion gallons * 0.38 = 5.7 trillion gallons.
Now, we need to determine how many years it will take for the lake to reach 10% of its capacity, considering it will be reduced to 5.7 trillion gallons.
Using similar proportions, if 38% represents 15 trillion gallons, then 10% (the desired amount) represents 5.7 trillion gallons / 0.38 = 15 trillion gallons / 0.38 * 0.1 = 3.95 trillion gallons.
Therefore, we need to find out how many years it will take for the lake to lose 90% of its water, which is a difference of 5.7 - 3.95 = 1.75 trillion gallons.
If we assume the linear rate of water loss over time, it would take 20 years to lose 1.75 trillion gallons (from 5.7 trillion to 3.95 trillion).