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What is the derivative of 57+42e^(-t/28)?

What is f(3)=?

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Answer:

So, f(3) is approximately equal to 95.61336424

Explanation:

Let’s calculate the derivative:

f’(t) = 0 + 42 * (-1/28) * e^(-t/28)

= -1.5 * e^(-t/28)

So, the derivative of the function 57 + 42e^(-t/28) is -1.5 * e^(-t/28).

Now, to find f(3), we substitute t = 3 into the function:

f(3) = 57 + 42e^(-3/28)

To get the exact numerical value, we need the specific value of e, but let’s simplify it in terms of e:

f(3) ≈ 57 + 42 * 0.89483932

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