Answer:
3(x-5)^2=48
3(x-5)^2-48=0
3(x²-10x+25)-48=0
3x²-30x²+75-48=0
3x²-30x+27=0
b²-4ac = (-30)²-4(3*27)=576
Δ=576
(-b-√Δ)/2a =(30-24)/6=1
(-b+√Δ)/2a =(30+24)/6=9
solutions 1;9
Explanation:
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