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What are the possible solutions of 3(x-5)^2=48

User Svish
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1 Answer

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Answer:

3(x-5)^2=48

3(x-5)^2-48=0

3(x²-10x+25)-48=0

3x²-30x²+75-48=0

3x²-30x+27=0

b²-4ac = (-30)²-4(3*27)=576

Δ=576

(-b-√Δ)/2a =(30-24)/6=1

(-b+√Δ)/2a =(30+24)/6=9

solutions 1;9

Explanation:

User Jkrnak
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