Question

NO LINKS!! URGENT HELP PLEASE!!
Please help me with this solution. ​

Answer 1

Explanation:

since they give you the question a 24 sin 5x equals to 4 between 0 and 33 give your answer in degrees so your answer is going to be number a cause cuz they say I give your answer in degrees or your number is going to be A

Answer 2

b) 18°, 90°, 162°, 234°, 306°

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Explanation:

Given equation:

`4 \sin (5x)=4`

To find the solutions to the given equation between 0° and 360°, first isolate the sine term and then solve for x.

Isolate the sine term by dividing both sides of the equation by 4:

`\begin{aligned}4 \sin (5x)&=4\\\\\sin(5x)&=1\end{aligned}`

Solve for 5x by taking the arcsine of both sides of the equation, remembering that the sine function has a periodicity of 2π and is positive in quadrants I and II.

`\begin{aligned}\arcsin \left(\sin(5x)\right)&= \arcsin \left(1\right)\\\\5x&=90^(\circ)+360^(\circ)n\end{aligned}`

Divide both sides of the equation by 5 to solve for x:

`\begin{aligned}(5x)/(5)&=(90^(\circ)+360^(\circ)n)/(5)\\\\x&=18^(\circ)+72^(\circ)n\end{aligned}`

To find the solutions for x that are in the given interval 0° < x < 360°, add integer multiples of 72° to the found solution:

`x=18^(\circ)`

`x=18^(\circ)+72^(\circ)=90^(\circ)`

`x=18^(\circ)+2(72^(\circ))=162^(\circ)`

`x=18^(\circ)+3(72^(\circ))=234^(\circ)`

`x=18^(\circ)+3(72^(\circ))=306^(\circ)`

Therefore, the solutions in the given interval are:

`\large\boxed{x=18^(\circ), 90^(\circ), 162^(\circ), 234^(\circ), 306^(\circ)}`