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Use the graph to answer the question. Graph of polygon ABCDE with vertices at negative 3 comma 5, negative 3 comma 8, 1 comma 8, 1 comma 5, negative 1 comma 3. A second polygon A prime B prime C prime D prime E prime with vertices at 13 comma 5, 13 comma 8, 9 comma 8, 9 comma 5, 11 comma 3. Determine the line of reflection. Reflection across the x-axis Reflection across the y-axis Reflection across x = 5 Reflection across y = 6

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How to get get A'B'C'D'E', you would have to reflect
ABCDE across the Y axis at X = 5.
User AlexDenisov
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Answer

In order to get A'B'C'D'E', you would reflect ABCDE across the Y axis at X = 5.

Explanation:

The easiest to explain this is you are essentially placing the Y axis at X = 5. In this case, we are setting a vertical line at (5, ∞) , and you can reflect your figure across that from it's current position.

In the first picture, you can see the two figures, and the new line at X = 5.

The second picture shows how the figure is reflected and mapped onto A'B'C'D'E'.

If you need a general overview of how to do reflections or just want to watch a neat video, I have one on my channel, Simpl Algebra

Use the graph to answer the question. Graph of polygon ABCDE with vertices at negative-example-1
Use the graph to answer the question. Graph of polygon ABCDE with vertices at negative-example-2
User Dupinder Singh
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