Question

How two sepearte 50 dB sounds together constitute 53 db

Answer 1

Step-by-step explanation:

When combining two separate sounds, we can use the formula for adding sound levels in decibels (dB) to calculate the resulting sound level.

The formula for combining two sound levels (in dB) is given by:

L_total = 10 * log10(10^(L1/10) + 10^(L2/10))

where:

L_total = the total sound level in dB when the two sounds are combined

L1 = the first sound level in dB

L2 = the second sound level in dB

In this case, we have two separate 50 dB sounds. Let's use the formula to find the total sound level when they are combined:

L_total = 10 * log10(10^(50/10) + 10^(50/10))

L_total = 10 * log10(10^5 + 10^5)

L_total = 10 * log10(100000 + 100000)

L_total = 10 * log10(200000)

Now, calculate the value inside the logarithm:

10 * log10(200000) ≈ 10 * 5.301

Finally, calculate the total sound level:

L_total ≈ 53.01 dB

So, when two separate 50 dB sounds are combined, the resulting sound level is approximately 53.01 dB.