Question

Jermo received 2 more dimes than quarters in exchange for a $10 bill. How many dimes did he receive?​

Answer 1

30 dimes

Explanation:

Let's use algebra to solve the problem.

Let x be the number of quarters that Jermo received. Then the number of dimes he received is 2 more than that, so we can express it as x + 2.

The value of x quarters is 25x cents, and the value of (x + 2) dimes is 10x + 20 cents. We know that Jermo received $10, which is 1000 cents, so we can write an equation:

25x + 10x + 20 = 1000

Simplifying this equation, we get:

35x + 20 = 1000

35x = 980

x = 28

So Jermo received 28 quarters, and the number of dimes he received is 2 more than that, or 28 + 2 = 30 dimes.

Therefore, Jermo received 30 dimes.

Answer 2

Let's use algebra to solve this problem. Let's say Jermo received x quarters and (x + 2) dimes.

The value of x quarters is 25x cents (since each quarter is worth 25 cents).

The value of (x + 2) dimes is 10(x + 2) cents (since each dime is worth 10 cents).

The total value received is $10, which is equivalent to 1000 cents.

So, we can set up the equation:

25x + 10(x + 2) = 1000

Now, let's solve for x:

25x + 10x + 20 = 1000

Combine like terms:

35x + 20 = 1000

Subtract 20 from both sides:

35x = 980

Divide by 35:

x = 980 / 35

x = 28

Jermo received 28 quarters. Now, to find the number of dimes (x + 2), we can substitute x = 28 into the expression:

Number of dimes = x + 2

Number of dimes = 28 + 2

Number of dimes = 30

Jermo received 30 dimes.