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Alvin wanted to buy some toy cars. If he bought three toy cars he would have $50 left. If. He bought seven toy cars he would have $6 left. How much did Alvin have at first

User Leemicw
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Answer: Let's use algebra to solve this problem. Let's assume that the cost of each toy car is "x," and Alvin had "y" dollars initially.

According to the given information:

If Alvin bought three toy cars, he would have $50 left. This can be represented by the equation: y - 3x = 50.

If Alvin bought seven toy cars, he would have $6 left. This can be represented by the equation: y - 7x = 6.

Now, we have a system of two equations:

y - 3x = 50

y - 7x = 6

To solve this system, we can use the method of substitution or elimination. Let's use the elimination method:

Subtract equation (2) from equation (1):

(y - 3x) - (y - 7x) = 50 - 6

y - 3x - y + 7x = 44

4x = 44

Now, solve for "x":

x = 44 / 4

x = 11

Now that we know the cost of each toy car is $11, we can find the value of "y" (the amount Alvin had initially) by substituting the value of "x" into either equation (1) or (2):

y - 3x = 50

y - 3(11) = 50

y - 33 = 50

y = 50 + 33

y = 83

So, Alvin had $83 initially.

User Smokefoot
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