Question

Electric field due to 9nc at a distance 3m in air is​

Answer 1

9N/C

Step-by-step explanation:

We know that,

E = kq/r²

where the symbols have their usual meanings.

On substituting the respective values, we have;

E = 9 × 10⁹ × 9 × 10-⁹ / (3)²

E = 81/9 N/C

E = 9N/C

Hence the required electric field is 9N/C