Answer:
Yes , No
Explanation:
to determine if the given point is a solution to the system
substitute the coordinates of the point into the left side of each equation and if equal to the right side then it is a solution.
Note for the point to be a solution of the system BOTH equations must be True
(63)
substitute x = 3 , y = 1 into the left sides and compare with right side
x + 3y = 3 + 3(1) = 3 + 3 = 6 ← True
4x - 5y = 4(3) - 5(1) = 12 - 5 = 7 ← True
both equations are True , then (3, 1 ) is a solution
(64)
substitute x = 6 , y = - 2 into the the left sides and compare with right side
3x - 2y = 3(6) - 2(- 2) = 18 + 4 = 22 ≠ 14 ← False
5x - y = 5(6) - (- 2) = 30 + 2 = 32 ← True
since Both equations are not true then (6, - 2 ) is not a solution