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Write an equation of a hyperbola with foci at (0,13) and (0,-13) and vertices at (0,5) and (0,-5).

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Answer:

x^2 / 25 - y^2 / 169 = 1

Explanation:

To write the equation of a hyperbola with given foci and vertices, we can start by determining the key properties of the hyperbola.

1. The foci of the hyperbola are located at (0,13) and (0,-13). This means that the distance from the center of the hyperbola to each focus is 13 units.

2. The vertices of the hyperbola are located at (0,5) and (0,-5). The distance from the center to each vertex is 5 units.

The standard form of the equation for a hyperbola centered at the origin is:

x^2 / a^2 - y^2 / b^2 = 1

where 'a' represents the distance from the center to the vertices, and 'b' represents the distance from the center to the foci.

In this case, we have a = 5 (distance from the center to the vertices) and b = 13 (distance from the center to the foci).

Plugging in these values, we get:

x^2 / 5^2 - y^2 / 13^2 = 1

Simplifying, we have:

x^2 / 25 - y^2 / 169 = 1

Therefore, the equation of the hyperbola with foci at (0,13) and (0,-13) and vertices at (0,5) and (0,-5) is:

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