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Convert y = x^2 - 6x + 11 to vertex form

1 Answer

5 votes

Answer:

y = (x - 3)² + 2

Explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

given

y = x² - 6x + 11

using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² - 6x

y = x² + 2(- 3)x + 9 - 9 + 11

y = (x - 3)² - 9 + 11

y = (x - 3)² + 2 ← in vertex form

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