Question

A 15. Given a= 2, b = -3 and c = 4. What is the value of 4a²bc + 3ab²c + c² A. 40 B.-164 C.-192 D.184​

Answer 1

Answer: A. 40

Explanation:

4a²bc + 3ab²c + c²

4(2)²(-3)(4) + 3(2)(-3)²(4) + (4)²

By inputting the numbers the answer should come out to be 40!

Answer 2

Answer: 40 (choice A)

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Work Shown:

`4a^2bc + 3ab^2c + c^2\\\\4(2)^2(-3)(4) + 3(2)(-3)^2(4) + 4^2\\\\4(4)(-3)(4) + 3(2)(9)(4) + 16\\\\-192 + 216 + 16\\\\24 + 16\\\\40\\\\`

Therefore,
`4a^2bc + 3ab^2c + c^2=40 \ \text{ when } a = 2, b = -3, c = 4\\\\`

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Explanation: Replace 'a' with 2, b with -3, and c with 4. Then use the order of operations PEMDAS to simplify.