A 15. Given a= 2, b = -3 and c = 4. What is the value of 4a²bc + 3ab²c + c² A. 40 B.-164 C.-192 D.184

Question

asked Jun 6, 2024 219k views

2 Answers

Jordan Clark · Answer 1 · 2024-06-09T01:11:56+0000

Answer: A. 40

Explanation:

4a²bc + 3ab²c + c²

4(2)²(-3)(4) + 3(2)(-3)²(4) + (4)²

By inputting the numbers the answer should come out to be 40!

Visst · Answer 2 · 2024-06-11T21:59:02+0000

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Work Shown:

$4a^2bc + 3ab^2c + c^2\\\\4(2)^2(-3)(4) + 3(2)(-3)^2(4) + 4^2\\\\4(4)(-3)(4) + 3(2)(9)(4) + 16\\\\-192 + 216 + 16\\\\24 + 16\\\\40\\\\$

Therefore,
$4a^2bc + 3ab^2c + c^2=40 \ \text{ when } a = 2, b = -3, c = 4\\\\$

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Explanation: Replace 'a' with 2, b with -3, and c with 4. Then use the order of operations PEMDAS to simplify.