Question

What amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C. A. 1200 joules B. 1500 joules C. 1700 joules D. 1900 joules E. 2000 joules

Answer 1

C. 1700 joules

Step-by-step explanation:

q=mC(T−T₀),

where q is the amount of heat,

m is the mass,

C is the specific heat capacity,

T is the final temperature,

and T₀ is the initial temperature.

Given:

m = 20 g

C = 4.18 J/g/°C

T = 30°C

T₀ = 10°C

Find: q

q = (20 g) (4.18 J/g/°C) (30°C − 10°C)

q = 1672 J

Rounding to two significant figures, the amount of heat required is 1700 joules.